Home
Class 12
PHYSICS
A charge of 0.8C is divided into two cha...

A charge of `0.8C` is divided into two charges `Q_(1) and Q_(2)`. These are kept at a separation of 30 cm. The force on `Q_(1)` is maximum when

A

`Q_(1)=Q_(2)=0.4C`

B

`Q_(1)~~0.8C` negligible

C

`Q_(1)` negligible, `Q_(2)~~0.8C`

D

`Q_(1)=0.2C,Q_(2)=0.8C`

Text Solution

Verified by Experts

We have `Q_(1)+Q_(2)=0.8C`
Therefoe, the force of attraction between the two charges,
`F=(Q_(1)Q_(2))/(4pi epsi_(0)r^(2))=(Q_(1)(0.8-Q_(1)))/(4pi epsi_(0) xx(30xx10^(-2))^(2))`
This force will be maximum if `(dF)/(dQ_(1))=0`
`:. (d)/(dQ_(1))[ (Q_(1)(0.8-Q_(1)))/(4pi epsi_(0)xx(30xx10^(-2))^(2))]=0`
or, `Q_(1) =0.4 C and Q_(2)=0.8-0.4=0.4C`
The option (A) is correct.
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC FIELD

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE ( JEE MAIN )|3 Videos

  • ELECTRIC FIELD

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE ( AIPMT)|1 Videos

  • ELECTRIC FIELD

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE (WBCHSE)|13 Videos

  • ELECTRIC ENERGY AND POWER

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|7 Videos

  • ELECTRIC POTENTIAL

    CHHAYA PUBLICATION|Exercise CBSE Scanner|13 Videos

Similar Questions

Explore conceptually related problems

A charge of 0.8 coulomb is divided into two charges Q_(1) and Q_(2) . These are kept at a separation of 30 cm. The force on Q_(1) is maximum when

A charge Q is divided into two equal parts q=(Q)/(2) . If the chages q and q are placed at certain distance,

A charge having magnitude Q is divided into two parts q and (Q-q). If the two parts exert a maximum force of repulsion on each other,then find the ratio Q/q.

The points on the line joining two charges +q and 3q (kept at a distance of 1.0 m) where electric potential is zero.

An amount of charge Q is distributed between two particles. What should be the charges of the two particles so the force of interaction between them is maximum ?

A+250 esu of charge P is On the line joining other two charges Q ( +50 esu of charge ) and R(-300 esu of charge) in between them. Distance of P from Q is 5 cm and from R it is 10 cm. What the resultant force acting on P? (##CHY_DMB_PHY_XII_P1_U01_C02_SLV_006_Q01.png" width="80%">

Two point charges q_1 and q_2 are such that q_1q_2 lt 0 . What is the nature of the force acting between the two charges?