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A suface has the area vector vecA(2hati...

A suface has the area vector `vecA(2hati + 3hatj)` what is the flux erof a uniform electric though the area if the field is a`vecE=4hatiN//C and vecE = 4 hatkN//C` ?

A

`0; 8N - m^(2)//C`

B

`8N - m^(2)//C; 8N - m^(2)//C`

C

`8N - m^(2)//C; 0`

D

`0; 0`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The unit vector of a vector vecA =2hati + 4hatj is

    A
    `9/sqrt20(hati+hatj)`
    B
    `sqrt20(2hati+3hatj)`
    C
    `1/sqrt20(2hati+4hatj)`
    D
    `9sqrt20(hati+hatj)`

  • Electric flux in an electric field vecE through area vector vec(ds) is given by

    A
    `vecExxvec(ds)`
    B
    `vecE*vec(ds)`
    C
    `vecE//vec(ds)`
    D
    `vec(ds)//vecE`

  • Given : vecE=(10hati+7hatj)Vm^(-1) . The electric flux through 1m^(2) area is XZ plane is

    A
    10 Vm
    B
    7Vm
    C
    100 Vm
    D
    49Vm