To reduce the action of the galvanometer by 25 times,a shunt is added to it. IF the galvanometer resistance is `1000 Omega` what is the resistance of the stunt?

Explanation

`I_G=I.S/(S+G)or,I_G/I=S/(S+G)`
According to the equation `I_G/I=1/25`
`therefore1/25=S/(S+G)or,25S=S+Gor,24S=1000`
`or,S=1000/24=41.67 Omega`