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In a metallic conductor, the number of f...

In a metallic conductor, the number of free electrons per unit volume is n and the drift velocity of those electrons is `v_d`. Then

A

`v_d prop n`

B

`v_d prop1/n`

C

`v_d prop n^2`

D

`v_d prop 1/n^2`

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The correct Answer is:
B
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If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. The radii of two wires ,made of two different metals are in the ratio 1:2 , The number density of free electrons in the first metal is double that in the second metal. IF the current in the first wire is 1A, then the current in the second wire producing the same drift velocity is

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CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( MULTIPLE CHOICE QUESTION)
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