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Two resistances 1 Omega and 2 Omega are...

Two resistances `1 Omega ` and `2 Omega` are connected in parallel and a potential difference of 6V is applie across the ends this combination, Calculate the current through the second conductor.

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3A
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CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( VERY SHORT ANSWER TYPE QUESTION)
  1. How are different electrical appliances connected In domestic electric...

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  2. Two resistances 1 Omega and 2 Omega are connected in series and a pote...

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  3. Two resistances 1 Omega and 2 Omega are connected in parallel and a p...

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  4. What is the value of I in the circuit of Fig.1.64?

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  5. Equivalent resistance in a parallel combination is ...... than each of...

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  6. Two resistance of 6 Omega and 3 Omega are connected in parallel when ...

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  7. A metallic wire of resistance R is folded into two equal parts and the...

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  8. The resistance of an electrical appliance is 200 Omega and it can with...

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  9. The equivalent resistance of two resistances in series is four times t...

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  10. Three resistances,each of 4 Omega, are connected in the form of an equ...

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  11. Name the quantity for which the potential difference of a cell becomes...

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  12. What is the maximum value of current available from a cell of emf 1.5 ...

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  13. IF the through a circuit or the of a cell be zero, then the value of ...

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  14. Emf, of a cell is 1.5 Vand its internal resistance is 1 Omega When the...

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  15. When a stunt of 1 Omega is connected in parallel with a galvanometer 1...

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  16. If the current through a galvanometer of resistance G is to be reduced...

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  17. A shunt of 1 Omega is connected in parallel with a galvanometer of res...

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  18. n electric cells having emf e and internal resistance r each are conne...

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  19. n electric cells of emf e and internal resistance r each are connected...

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  20. In metallic conductor of conventional current is to the direction of f...

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