When the two electrodes of an electric cell are connected directly with a voltmeter,it gives a reading of 1.2 V,State whether this value can be called the emf of the cell?

Emf of an electric cell is 2.1 V and its internal resistance is 0.1 Omega . When the two poles of the cell are connected with an external resistance, a potential difference of 2.08 V is obtained. Determine the value of the external resistance.

When a voltmeter of resistance 100 Omega is connected with an electric cell, the reading of the voltmeter is 2V. When the cell is connected with a resistance of 15 Omega . An ammeter of resistance 1 Omega given the reading of 0.1 A.Determine the emf of the cell.

The emf of a dry cell is 1.5 V , when an ammeter and a resistance are connected with the series combination of two dry cells in series,then the ammeter reads 1A,and when the cells are connected in parallel the reading of the ammeter becomes 0.75A What is the internal resistance of the dry cell? Draw the circuit diagrams?

Statement I: The voltmeter reading does not denote the correct emf of an electric cell,when the terminals of the cell are directly connected to the voltmeter. Statement II: As every electric cell has some internal resistance,the current in the external circuit is reduced to some extent.

A closed circuit consists of n cells connected in series. Each cell has an emf e and internal resistance r. The resistance of the connecting wires is assumed to be zero. What will be the reading of voltmeter connected to the terminals of one of the cells? It is assumed that the voltmeter has an infinitely high resistance as usual. Can it be real in practice?

With a uniform potentimeter wire AB of resistance 100Omega , an electric cell of negligible internal resistance and a voltmeter 360 Omega is connected in between A and the mid -point C of the wire . If the reading of the voltmeter be 1.0 V , determine the emf of the cell .

Statement I : a potentimeter arrangement is more suitable than a voltmeter arrangement for the accurate measurement of the emf of an electric cell . Statement II : It is possible to connect an electric cell in a potentimeter circuit in such a way that no current passes through the cell .

A voltmeter and an ammeter are connected in series to an ideal cell of emf E. The voltmeter readings is V and the ammeter reading is I. Choose the correct options.

A number of cells of negligible resistance are connected with battery of 12V with two resistances in series.A voltmeter of resistances 5000 Omega while connected with these two resistances reads 4V and 6V respectively.Find the magnitude of the resistances.

A cell of emf 1.4V and internal resistance 2 Omega is connected in series with a resistance of 100 Omega and an ammeter. The resistance of the ammeter is 4/3 Omega .To measure the potential difference between the two ends of the resistance a voltmeter is connected IF the reading of the ammter is 0.02 A.what is the resistance of the voltmeter?