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Due to a mistake in the designing an amm...

Due to a mistake in the designing an ammeter is joined is parallel to a resistance of a circuit amd a voltmeter in series with it.What will be the consequences?

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By mistake, a voltmeter is connected in series and an ammeter in parallel with a resistance in an electric circuit. What will happen to the measurements?

Statement I: Out of galvanometer ,ammeter and voltmeter , resistance of ammeter is lowest and resistance of voltmeter is highest. Statement II: AN ammeter is connected in series and a voltmeter is connected in parallel, in a circuit.

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Two identical cells each of emf 1.5V are connected in series. IF this combination of cells is connected to a resistance and a galvanometer in series, the current that flows through the circuit is 1A.If the cells are connected in parallel the current becomes 0.6 A, Determine the internal resistance of each cell.

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. What is the resistance of voltmeter.

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The voltmeter reads 1.10V. What is the error in the reading ?

A cell of emf 3.4V and internal resistance 3Omega is connected to an ammeter having resistance 2Omega . and to an external resistance of 100Omega . When a voltmeter is connected across the 100Omega resistance the ammeter reading is 0.04A. Find the voltage read by the voltmeter and its resistance. Had the voltmeter been an ideal one what would have been its reading ?

A shunt of 1 Omega is connected in parallel with a galvanometer of resistance 99 Omega . IF the main current of the circuit be 1A, then what will be the galvanometer current?

The terminal potential difference of galvanometter is 1 V for its full-scale deflection. A resistance of 950Omega , connected in series with it, converts it to a voltmeter that can read a maximum of 20 V. What is the resistance of the galvanometer?

CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( SHORT ANSWER TYPE QUESTION-I)
  1. Show that if the two electrodes of an electric cell are short circuite...

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  2. Show that in a closed circuit the potential difference between the two...

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  3. In household electrical wiring how are the lights and fans are connect...

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  4. Show that the terminal potential difference of a cell connected in a c...

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  5. Show that the equivalent resistance of a series combination is greater...

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  6. Show that the equivalent resistance of a parallel combination is less ...

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  7. IF two resistor are connected in parallel,their equivalent resistance ...

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  8. You are given 'n' resistors,each of resistance 'r'.These are first con...

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  9. The capacity of a secondary cell is 30 A.h what is the meaning of this...

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  10. Due to a mistake in the designing an ammeter is joined is parallel to ...

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  11. IF the electron drift speed is so small and the electron's charge is a...

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  12. A carbon resistor of 41k Omega is to be marked with rings of different...

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  13. IF the current supplied to a variable resistor is constant, draw a gra...

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  14. Name any one material having a small value of temperature coefficient ...

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  15. How does the conductance of a semiconducting material change with rise...

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  16. The electron drift speed is estimated to be only a few mm.s^-1 for cur...

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  17. Draw a graph to show the variation of resistance of a metal wire as a ...

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  18. What happends to the drift velocity of electrons and to the resistanc...

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  19. IF potential differences V applied across a conductor is increased to ...

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  20. Draw the graph showing variation of resistivity with temperautre for s...

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