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Emf of an electric cell is 1.5 V and its...

Emf of an electric cell is 1.5 V and its internal resistance Is `2 Omega`. With this cell `1 Omega, 2 Omega` and `10 Omega` resistances are arranged in series .Determine the terminal potential differences of the resistances and the lost volt.

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The correct Answer is:
0.1V,0.2V,1.0V,0.2V
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CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( PROBLEM SET-I)
  1. With two resistances 2 Omega and 3 Omega In parallel a third resistanc...

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  2. Equivalent resistances of two resistors in their series and parallel c...

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  3. The equivalent resistances of two resistances in parallel combination ...

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  4. There are 14 resistances each of magnitude 1 Omega. Keeping three of t...

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  5. The resistance of an electrical appliance is 200 Omega and it can with...

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  6. The ratio of three resistances is 1:2:3 if the greatest resistance be ...

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  7. Emf of an electric cell is 2.1 V and its internal resistance is 0.1 Om...

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  8. Emf of an electric cell is 1.5 V and its internal resistance Is 2 Omeg...

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  9. A cell of emf 2.1 V and 0.1 Omega internal resistance sends 100 mA cur...

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  10. Electric current is sent through a resistance of 20 Omega from a batte...

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  11. Internal resistance of an electric cell is 1 Omega. Error is incurred ...

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  12. Current is sent from an electric cell of emf 30 V and of negligible in...

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  13. An electric cell of emf 2V and of negligible internal resistance is co...

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  14. Internal resistance of each of 30 identical cells is 3Omega. To get th...

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  15. Emf of each of 15 cells is 2V and internal resistance of each is 0.1 O...

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  16. 5 electric cells are connected in series .Emf of each cell is 1.5 V an...

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  17. When a resistance of 4.5 Omega is connected with 10 identical cells in...

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  18. Calculate the number of electrons crossing a given cross section in 1 ...

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  19. The number of free electrons per unit volume in a metallic conductor i...

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  20. Estimate the average drift speed of conduction electrons in a copper w...

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