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A wire of 15 Omega resistance is gradual...

A wire of `15 Omega` resistance is gradually stretched to double its length . IT is then cut into two equal parts. These parts are then connected in parallel across a 3.0 volt battery .Find the current drawn from the battery.

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0.2A
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CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( PROBLEM SET-II)
  1. A metallic wire is stretched to increase its length by 20% .What will ...

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  2. A wire of unifrom cross section is made from 1g of copper whose resist...

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  3. A wire of 15 Omega resistance is gradually stretched to double its len...

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  4. According to the definition of International ohm, the resistance of a ...

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  5. The coefficient of linear equation of copper is 17times10^-6//^@C and ...

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  6. Two wires are of lengths 1 cm and 2 cm and their diameters are 1 mm an...

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  7. With a series combination of 1 Omega and 2 Omega resistances another s...

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  8. A quadrilateral ABCD is made of conducting wires AB=3 Omega,BC=2 Omega...

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  9. 5A current is divided into three parallel branches in a circuit.The ra...

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  10. An electric cell of emf 10 V and of internal resistance 1 Omega is con...

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  11. Three resistances 8 Omega,20 Omega and 40 Omega are connected in paral...

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  12. An electric cell is sending electric currents through a resistance of ...

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  13. A parallel combination of three resistances of 6 Omega, 12 Omega and 1...

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  14. Three resistances of 4 Omega , 5Omega and 12 Omega are connected in p...

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  15. The resistances of a galvanometer is 200 Omega and full-scale deflecti...

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  16. Current is sent through a galvanometer of resistance 50 Omega from a b...

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  17. A shunt is connected with a galvanometer in such a way that 1/90 part ...

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  18. A resistor of magnitude 45 Omega is connected to an electric cell of e...

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  19. Two resistor of magnitudes 300 Omega and 400 Omega are connected with ...

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  20. A number of cells of negligible resistance are connected with battery ...

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