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Three resistances 8 Omega,20 Omega and 4...

Three resistances `8 Omega,20 Omega` and `40 Omega` are connected in parallel and the combination is joined to a cell of emf 2.1 V. IF current through the lowest resistances is 0.25A, determine the terminal resistance of the cell.

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The correct Answer is:
`0.25 Omega`
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CHHAYA PUBLICATION-CURRENT ELECTRICITY -EXERCISE ( PROBLEM SET-II)
  1. Two wires are of lengths 1 cm and 2 cm and their diameters are 1 mm an...

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  2. With a series combination of 1 Omega and 2 Omega resistances another s...

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  3. A quadrilateral ABCD is made of conducting wires AB=3 Omega,BC=2 Omega...

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  4. 5A current is divided into three parallel branches in a circuit.The ra...

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  5. An electric cell of emf 10 V and of internal resistance 1 Omega is con...

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  6. Three resistances 8 Omega,20 Omega and 40 Omega are connected in paral...

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  7. An electric cell is sending electric currents through a resistance of ...

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  8. A parallel combination of three resistances of 6 Omega, 12 Omega and 1...

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  9. Three resistances of 4 Omega , 5Omega and 12 Omega are connected in p...

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  10. The resistances of a galvanometer is 200 Omega and full-scale deflecti...

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  11. Current is sent through a galvanometer of resistance 50 Omega from a b...

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  12. A shunt is connected with a galvanometer in such a way that 1/90 part ...

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  13. A resistor of magnitude 45 Omega is connected to an electric cell of e...

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  14. Two resistor of magnitudes 300 Omega and 400 Omega are connected with ...

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  15. A number of cells of negligible resistance are connected with battery ...

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  16. A cell AB of resistance 500 Omega is connected to a battery of emf 12 ...

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  17. A certain circuit with resistance R-100 Omega is powered by a direct c...

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  18. 5 Identical cells are connected in series to form a row, 3 such rows a...

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  19. The emf of a dry cell is 1.5 V , when an ammeter and a resistance are ...

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  20. A series combination of n identical cells has two cells P and Q with r...

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