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A shunt of resistance r1 is connected in...

A shunt of resistance `r_1` is connected in parallel with a galvanometer of resistance G. A steady source of internal resistance r sends current through the galvanometer.Now, removing the shunt `r_1` another resistances `r_2` is connected in series with the galvanometer. (i) IF the galvanometer current in either case be the same , show that `rG=r_1r_2,` (ii) if r=0 and `r_1=r_2=G/n`, then show that the ratio of galvanometer currents in the two cases is `(n+1)/n`.

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