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Two wire of same radius having lengths t...

Two wire of same radius having lengths `t_1` and `t_2` and resistivities `rho_1` and `rho_2` are connected in series. The equivalent resistivity will be

A

`(rho_1l_2+rho_2l_1)/(rho_1+rho_2)`

B

`(rho_1l_1+rho_2l_2)/(l_1+l_2)`

C

`(rho_1l_1-rho_2l_2)/(l_1-l_2)`

D

`(rho_1l_2-rho_2l_1)/(l_1+l_2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(rho_1l_1)/A+(rho_2l_2)/A=rho_(eq)((l_1+l_2))/A`
`thereforerho_(eq)=(rho_1l_1+rho_2l_2)/(l_1+l_2)`
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