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A carbon resistor of (47 pm 4.7) k Omega...

A carbon resistor of `(47 pm 4.7) k Omega` is to be marked with rings of different colours for its identification. The colour code sequence will be

A

Yellow-Green-Violet-Gold

B

Yellow-Violet-Orange-Silver

C

Violet-Yellow-Orange-Silver

D

Green-Orange-Violet-Gold

Text Solution

Verified by Experts

The correct Answer is:
B
`(47pm4.7)=47pm(4.7/4.7times100)%=47pm10%`
`therefore(47pm4.7)kOmega=47times10^3pm 10% Omega`
Therefore, the colour code sequence will be yellow-violet-orange-silver
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