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The length of a bar magnet is 20 cm and ...

The length of a bar magnet is 20 cm and its magnetic moment is 0.6 A `m^(2)` . Determine the magnetic field at a point on the axis of the magnet and 30 cm away from the north pole .

Text Solution

Verified by Experts

In Fig
PN=PS = 30 cm = 0.3 m = `sqrt(d^(2)+l^(2))`
Magnetic field at the point p due to the magnet ,
` B=(mu_(0))/(4pi).(p_(m))/((d^(2)+l^(2))^(3//2))`
`=(4pixx10^(-7))/(4pi)xx(0.6)/((0.3)^(3))=2.22xx10^(-6)"Wb".m^(-2)`
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