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The angle of dip at a place is 30^(@) an...

The angle of dip at a place is `30^(@)` and the horizontal component of earth ' s magnetic field at that place is 0.39 CGS units . Determine the vertical component of earth's magnetic field at that place .

Text Solution

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Here , `theta = 30^(@)andH=0.39` CGS units.
If the intensity of the earth's magnetic field be I , then
`H=Icostheta" or, " I=(H)/(costheta)`
Vertical component ,
`V=Isintheta=(H)/(costheta).sintheta=Htantheta`
`=0.39xxtan30^(@)=0.39xx(1)/sqrt(3)=0.225 ` CGS units
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