At a place , the angle of declination is `30^(@)E` and the angle of dip is `45^(@)N` . Determine the horizontal and vertical components of the geomagnetic intensity in geographical meridian at that place. Given , the horizontal component of earth's magnetic field at that place = 0.3 Oe .

Explanation

Here , `=delta=30^(@)E, theta =45^(@)N and H = 0.3 "Oe " `
If the horizontal components of earth's magnetic field in the geographical meridian be h' according to Fig

`H'=H cosdelta=0.3cos30^(@)=0.3xx(sqrt3)/(2)=0.2598 " Oe"`
Vertical component remains the same in the geographical and the magnetic meridian planes , hence
`V=Htan theta=0.3tan45^(@)=0.3xx1=0.3" Oe"`