A short bar magnet placed on a horizontal plane has its axis aligned along the magnetic north- south direction . Null points are found on the magnet . The earth's magnetic field at the place is 0.36G . What is the magnet at the total magnetic field on the normal bisector of the same distance as the null points (i.e., 14 cm) from the centre of the magnet (at null points , field due to a magnet is equal and opposite to the horizontal component of earth's magnetic field . )

Explanation

Axial magnetic field `B_(AX)` is equal to the geomagnetic field (=0.36) at the null points . Magnetic field at the equatorial line due to the equatorial line due to the magnet , `B_(eq)=(B_(ax))/(2)=(0.36)/(2)=0.18G`
`therefore` Total magnetic field at a point 14 cm away on the equatorial line ,
`B=B_(eq)+B_(ax)=0.36+0.18=0.54G`