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An electron in an atom is moving in a c...

An electron in an atom is moving in a circular in a circular orbit of radius `0.53Å` . If the frequency of revolution is `10^(10)MHz` , what is the magnetic dipole moment equivalent to the orbit of the electron ?

Text Solution

Verified by Experts

The correct Answer is:
`1.4xx10^(-23)A.m^(2)`
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Knowledge Check

  • An electron in a circular orbit of radius 0.5nm performs 10^16 revolutions per second the magnetic moment due to this rotation of electron is (in Am^2 )

    A
    `2.16xx10^(-23)`
    B
    `3.21xx10^(-22)`
    C
    `3.21xx10^(-24)`
    D
    `1.26xx10^(-21)`

  • An electron in a circular orbit of radius .05 nm performs 10^16 revolution per second the magnetic moment due to this rotatics of electron is(in Am^2 )

    A
    `2.16xx10^(-23)`
    B
    `3.21xx10^(-22)`
    C
    `3.21xx10^(-24)`
    D
    `1.26xx10^(-23)`

  • An electron in a circular orbit of radius 0.05nm performs 10^(16) revolutions per second. The magnetic moment due to this rotation of electron is (in A . m^(2) )

    A
    `2.16xx10^(-23)`
    B
    `3.21xx10^(-22)`
    C
    `3.21xx10^(-24)`
    D
    `1.26xx10^(-23)`

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