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The intensity of magnetsation of a bar m...

The intensity of magnetsation of a bar magnet is `5.0xx10^(4)A.m^(-1)` The magnetic length and area of cross section of the magnet are 12cm and `1 "cm"^(2)` Respectively. The magnitude of magnetic moment of this this bar magnet is (in SI unit)

A

`0.6`

B

`1.3`

C

`1.24`

D

`2.4`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of the bar magnet,
`V=0.12xx1xx10^(-4)=1.2xx10^(-5)m^(3)`
Intensity of magnetisation ,
`M=(p_(m))/(V) " " [p_(m)` = magnetic moment ]
`therefore" " p_(m)=MV=5.0xx10^(4)xx1.2xx10^(-5)=0.6A.m^(2)`
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