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An electron in a circular orbit of radiu...

An electron in a circular orbit of radius 0.05nm performs `10^(16)` revolutions per second. The magnetic moment due to this rotation of electron is (in A . `m^(2)` )

A

`2.16xx10^(-23)`

B

`3.21xx10^(-22)`

C

`3.21xx10^(-24)`

D

`1.26xx10^(-23)`

Text Solution

Verified by Experts

The correct Answer is:
D
Magnetic moment
`=IA=qnA`
`=(1.6xx10^(-19))xx10^(16)xxpi(0.05xx10^(-9))^(2)`
`=1.26xx10^(-23)`
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