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In the velocity of em wave in vacuum is ...

In the velocity of em wave in vacuum is `3xx10^8 m.s^(-1)` and the magnetic permeability of vacuum is `4pixx10^(-7)N.C^(-2) .s^(2)`, find the electric permittivity of vacuum.

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If permittivity and permeability of free space are `in_0` and `mu_0` , respectively,
`c=1/sqrt(in_0mu_0)` or , `c^2=1/(in_0mu_0)`
`therefore in_0=1/(mu_0c^2)=1/(4pixx10^(-7)xx9xx10^16)` [ `because mu_0 = 4pi xx 10^(-7) N. C^(-2) . S^2` and `c=3xx10^8 m.s^(-1)` ]
`=8.842xx10^(-12)C^2 . N^(-1) . m^(-2)`
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