Home
Class 12
PHYSICS
An EM wave radiates outward from a dipol...

An EM wave radiates outward from a dipole antenna, with `E_0` as the amplitude of its electric field vector. The electric field `E_0` which transports significant energy from the source falls off as

A

`1/r^3`

B

`1/r^2`

C

`1/r`

D

remains constant

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise EXERCISE (MCQ)|18 Videos
  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise EXERCISE (VERY SHORT ANSWER )|16 Videos
  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise NCERT TEXTBOOK QUESTIONS|23 Videos
  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|28 Videos
  • ELECTROMAGNETISM

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|26 Videos

Similar Questions

Explore conceptually related problems

A positively charged particle is released from rest in a uniform electric field. The electric potential energy of the charge

A red LED emits light a 0.1 watt uniformly around it. The amplitude of the electric field of the light at a distance of 1 m from the diode is

Which physical quantity is expressed by the ratio of the amplitudes of electric and magnetic fields for an electro magnetic wave.

An electron of charge -e and mas m is placed in a uniform electric field of intensity E. The value of E is such that the force on the electron due to the electric field is equal to its weight . Under this condition the value of E is

A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity on the axis of the ring at a distance x from its centre is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of E_(1) ?

A circular copper ring of radius r, placed in vacuum, has charge q on it. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of E_(2) ?

A circular copper ring of radius r, placed in vacuum, has charge q on ti. The electric field intensity at the centre of the ring is E_(1) . The electric field intensity of the axis of the ring at a distance x from its centres is E_(2) . The value of E_(2) will be maximum when x=x' What is the value of x' ?

An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall of the proton is

From the defination of an electric field, show that its unit in Si is V.m^(-1)

The electric force on an electron is equal to its weight in an electric field of intensity E. The charge of electron is e and mass is. m Then the value of E be—