How is the velocity of an electromagnetic wave in a medium related with the electric and the magnetic properties of that medium?

The velocity of electromagnetic wave is parallel to—

During the propagation of electromagnetic waves in a medium

‘Energy of an electromagnetic wave is equally shared between electric and magnetic fields’--explain your answer.

Amplitude of electric field of a plane electromagnetic wave is 48 V. m^(-1) . What is the amplitude of the magnetic field of the wave ?

Write down the relation among velocity of electromagnetic waves, magnetic permeability of vacuum and electric permittivity of vacuum.

c and v are the velocities of an electromagnetic wave in free space of permittivity in_0 and permeability mu_0 and in a medium of permittivity in and mu permeability respectively. If the refractive index of the medium is n, then which of the following relations are correct?

What are the quantities that oscillate in an electromagnetic wave? Show by means of a diagram, the relative orientation of the directions of the electric vector, magnetic vector and propagation of the electromagnetic wave.

Write down two properties of electromagnetic waves.

How is the speed of EM waves in vacuum determined by the electric and magnetic fields?

Electromagnetic waves propagate through free space or a medium as transverse waves. The electric and magnetic fields are perpendicular to each other as well as perpendicular to the direction of propagation of waves at each point. In the direction of wave propagation, electric field vecE and magnetic field vecB form a right-handed cartesian coordinate system. During the propagation of electromagnetic wave, total energy of electromagnetic wave is distributed equally between electric and magnetic fields. Since in_0 and mu_0 are permittivity and permeability of free space, the velocity of electromagnetic wave, c=(in_0 mu_0)^(-1//2) . Energy density i.e., energy in unit volume due to electric field at any point, u_E=1/2in_0E^2 Similarly, energy density due to magnetic field , u_M=1/(2mu_0)B^2 . If the electromagnetic wave propagates along x-direction, then the equations of electric and magnetic field are respectively. E=E_0sin(omegat-kx) and B=B_0sin(omegat-kx) Here, the frequency and the wavelength of oscillating electric and magnetic fields are f=omega/(2pi) and lambda=(2pi)/k respectively. Thus E_"rms"=E_0/sqrt2 and B_"rms"=B_0/sqrt2 , where E_0/B_0=c . Therefore, average energy density baru_E=1/2in_0E_"rms"^2 and baru_M=1/(2mu_0)B_"rms"^2 . The intensity of the electromagnetic wave at a point, I=cbaru=c(baru_E+baru_B) . To answer the following questions , we assume that in case of propagation of electromagnetic wave through free space, c=3xx10^8 m.s^(-1) and mu_0=4pixx10^(-7) H.m^(-1) If the peak value of electric field at a point in electromagnetic wave is 15 V . m^(-1) , then average electrical energy density (in j . m^(-3) )