Home
Class 12
PHYSICS
The peak value of the electric field of ...

The peak value of the electric field of a plane radio wave is `10^(-4) V.m^(-1)` .What is the peak value of the magnetic field?

Text Solution

Verified by Experts

`3.33xx10^(-13)T`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise EXERCISE (PROBLEM SET - II)|8 Videos
  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise EXERCISE (HOTS NUMBERICAL PROBLEMS )|3 Videos
  • ELECTROMAGNETIC WAVES

    CHHAYA PUBLICATION|Exercise EXERCISE (SHORT ANSWER TYPE QUESTION - II)|1 Videos
  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|28 Videos
  • ELECTROMAGNETISM

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|26 Videos

Similar Questions

Explore conceptually related problems

Amplitude of electric field of a plane electromagnetic wave is 48 V. m^(-1) . What is the amplitude of the magnetic field of the wave ?

What is the peak value of the voltage of a 220V ac line?

Due to the sunlight, if the amplitude of the electric field at the earth surface is 900 V . m^(-1) , then the amplitude of the magnetic field is nxx10^(-6) T. Find the value of n.

The peak of magnetic field for any electro magnetic wave is 20 nT. What will be the peak value of the electric field?

In a region of free space the average electric field of an electromagnetic wave is 9 xx 10^-4 NC^-1 . What is the magnetic field in that region?

If in air medium the amplitude of the electric field is 5 xx 10^-4v//m , then what will be the amplitude of the magnetic field?

Electromagnetic waves propagate through free space or a medium as transverse waves. The electric and magnetic fields are perpendicular to each other as well as perpendicular to the direction of propagation of waves at each point. In the direction of wave propagation, electric field vecE and magnetic field vecB form a right-handed cartesian coordinate system. During the propagation of electromagnetic wave, total energy of electromagnetic wave is distributed equally between electric and magnetic fields. Since in_0 and mu_0 are permittivity and permeability of free space, the velocity of electromagnetic wave, c=(in_0 mu_0)^(-1//2) . Energy density i.e., energy in unit volume due to electric field at any point, u_E=1/2in_0E^2 Similarly, energy density due to magnetic field , u_M=1/(2mu_0)B^2 . If the electromagnetic wave propagates along x-direction, then the equations of electric and magnetic field are respectively. E=E_0sin(omegat-kx) and B=B_0sin(omegat-kx) Here, the frequency and the wavelength of oscillating electric and magnetic fields are f=omega/(2pi) and lambda=(2pi)/k respectively. Thus E_"rms"=E_0/sqrt2 and B_"rms"=B_0/sqrt2 , where E_0/B_0=c . Therefore, average energy density baru_E=1/2in_0E_"rms"^2 and baru_M=1/(2mu_0)B_"rms"^2 . The intensity of the electromagnetic wave at a point, I=cbaru=c(baru_E+baru_B) . To answer the following questions , we assume that in case of propagation of electromagnetic wave through free space, c=3xx10^8 m.s^(-1) and mu_0=4pixx10^(-7) H.m^(-1) If the peak value of electric field at a point in electromagnetic wave is 15 V . m^(-1) , then average electrical energy density (in j . m^(-3) )

The magnitude of an electric field along x-axis is 1V.m^(-1) and in the same region the magnitude of a magnetic field along y-axis is 10^(-6) T . What should be the velocity of an electron in that region so that it will continue to move with uniform velocity along z-axis without suffering any deviation?

At a place , the horizontal component of earth's magnetic field is B and angle of dip is 60^(@) . What is the value of horizontal component of earth's magnetic field at equator ?

A proton is moving with a uniform velocity of 10^(6)m.s^(-1) along the Y-axis, under the joint action of a magnetic field along Z-axis and an electric field of magnitude 2xx10^(4)V.m^(-1) along the negative X-axis. If the electric field is switched off, the proton starts moving in a circle. The radius of the circle is nearly (given: (e)/(m) ratio for proton ~~10^(8)C.kg^(-1) )