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A condenser of capacity C(1) is charged ...

A condenser of capacity `C_(1)` is charged to a potential `V_(0)`. The electrostatic energy stored in it is `U_(0)`. It is connected to another uncharged condenser of capacity `C_(2)` in parallel. The energy dissipated in the process is

A

`(C_(2))/(C_(1)+C_(2))U_(0)`

B

`(C_(1))/(C_(1)+C_(2))U_(0)`

C

`((C_(1)-C_(2))/(C_(1)+C_(2)))U_(0)`

D

`(C_(1)C_(2))/(2(C_(1)+C_(2)))U_(0)`

Text Solution

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The correct Answer is:
A
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