In the circuit shown in figure , initial...

In the circuit shown in figure , initially key `K_(1)` is closed and key `K_(2)` is open. Then `K_(1)` is opened and `K_(2)` is closed (order is important). [Take `Q_(1)^(')` and `Q_(2)^(')` as charges on `C_(1)` and `C_(2)` and `V_(1)` and `V_(2)` as voltage respectively].

Then

Charge on `C_(1)` gets redistributed such that `V_(1)=V_(2)`

Charge on `C_(1)` gets redistributed such that `Q_(1) = Q_(2)`

charge on `C_(1)` gets redistributed such that `C_(1)V_(1)+C_(2)V_(2)=C_(1)E`

Charge on `C_(1)` gets redistributed such that `Q_(1)+Q_(2)=C_(1)E`

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The correct Answer is:

`(A,C,D)`

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In the circuit shown in figure , initially key `K_(1)` is closed and key `K_(2)` is open. Then `K_(1)` is opened and `K_(2)` is closed (order is important). [Take `Q_(1)^(')` and `Q_(2)^(')` as charges on `C_(1)` and `C_(2)` and `V_(1)` and `V_(2)` as voltage respectively].

Then