Home
Class 12
PHYSICS
Two resistance R(1) and R(2) are made of...

Two resistance `R_(1)` and `R_(2)` are made of different material. The temperature coefficient of the material of `R_(1)` is `alpha` and of the material of `R_(2)` is `-beta`. Then resistance of the series combination of `R_(1)` and `R_(2)` will not change with temperature, if `R_(1)//R_(2)` will not change with temperature if `R_(1)//R_(2)` equals

A

`alpha/beta`

B

`(alpha+beta)/(alpha-beta)`

C

`(alpha^(2) + beta^(2))/(alphabeta)`

D

`beta/alpha`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS|Exercise Combination of Resistance 1|14 Videos
  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS|Exercise Combination of Resistance 2|14 Videos
  • ELECTRIC CHARGES AND FIELDS

    CENGAGE PHYSICS|Exercise QUESTION BANK|40 Videos
  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS|Exercise Interger|8 Videos

Similar Questions

Explore conceptually related problems

Two resistances R_1 and R_2 are made of different materials. The temperature coefficient of the material of R_1 is alpha and of the material of R_2 is -beta . The resistance of the series combination of R_1 and R_2 will not change with temperature, if R_1//R_2 equals.

Two spheres of radii R_(1) and R_(2) are made of the same material and are at the same temperature. The ratio of their thermal capacities is:

The temperature coefficient of resistance for two material A and B are 0.0031^(@)C and 0.0068^(@)C^(-1) respectively .Two resistance R_(1) and R_(2) made from material A and B respectively . Have resistance of 200 Omega and 100 Omega at 0^(@)C . Show as a diagram the colour cube of a carbon resistance that would have a resistance equal to the series combination of r_(1) and R_(2) at a temperature of 100^(@)C (Neglect the ring corresponding to the tolerance of the carbon resistor)

Two spherical black bodies of radii R_(1) and R_(2) and with surface temperature T_(1) and T_(2) respectively radiate the same power. R_(1)//R_(2) must be equal to

Tow resistance R_(1) = 50 pm 2 ohm and R_(2) = 60 pm connected in series , the equivalent resistance of the series combination in

If resistors of resistance R_(1) and R_(2) are connected in parallel,then resultant resistance is "

Two wires of resistance R_(1) and R_(2) have temperature coeficient of resistance alpha_(1) and alpha_(2) respectively. These are joined in series. The effeictive temperature coefficient of resistance is

Calculate equivalent resistance of two resistors R_(1) and R_(2) in parallel where, R_(1) = (6+-0.2) ohm and R_2 = (3+-0.1)ohm