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A room AC run for 5 hour at a voltage of...

A room `AC` run for `5` hour at a voltage of `220V` The wiring of the room constant of `Cu` of `1mm` ratio and a length of `10 m` consumption per day is `10` commerclal unit What fraction of it goes in the joule heated in wire? What would happen if the wiring is made of aluminum of the same distances? `[rho_(cu) = 1.7 xx 10^(-8) Omega,rho_(A1) = 2.7 xx 10^(-8) Omega m]`

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A room AC run for 5 hour at a voltage of 220V The wiring of the room constant of Cu of 1mm radius and a length of 10 m consumption per day is 10 commerclal unit What fraction of it goes in the joule heated in wire? What would happen if the wiring is made of aluminum of the same distances? [rho_(cu) = 1.7 xx 10^(-8) Omega,rho_(A1) = 2.7 xx 10^(-8) Omega m]

A room has an A C which. runs for 5h a day at a voltage of 220 V . The wiring of the room consists of.Cu of 1 mun radius and a length of 10 m . The power consumption per day is 10 commercial units. What percentage of it goes in the joule heating of wires? (rho_(cal) = 1.7 xx 10^(-8) ohm m) .

Knowledge Check

  • When the resistance of copper wire is 0.1 Omega and the radius is 1mm, then the length of the wire is (specific resistance of copper is 3.14 xx 10^(-8) ohm xx m )

    A
    10 cm
    B
    10 m
    C
    100 m
    D
    100 cm
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    Find the resistance of a copper coil of total wire-length 10m and area of cross section 1.0mm^(2). What would be the resistance of a similar coil of aluminium? The resistivity of copper =1.7xx10^(-8)(Omega)m and that of aluminium 2.6xx10^(-8)(Omega).

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