(a^(2)-3a)(a^(2)-3a+7)+10

If (3a+7b)/(3a-7b)=(4)/(3) then find the value of the ratio (3a^(2)-7b^(2))/(3a^(2)+7b^(2))

If a+b+c=3 and agt0, bgt0, cgt0 then the greatest value of a^2b^3c^2= (A) (3^2)(2^3)(7^2) (B) (3^10 2^4)/7^7 (C) (3^7 2^5)/7^2 (D) (3^7 2^4)/7^7

Factorise : 3x^(3) + 14x^(2) - 7x - 10

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

(3)/(10)+(7)/(10^(2))+(3)/(10^(3))+(7)/(10^(4))+(3)/(10^(5))+(7)/(10^(6))+

State True or False : (7/3)^(2)xx(7/3)^(5)=(7/3)^(10)

1-(4)/(2)+(7)/(2^(2))-(10)/(2^(3))+

How much is a^2-3a greater than 2a^2+4a ? (A) a^2-7a (B) a^2+7a (C) -a^2-7a (D) a^2+7a

How much is a^2-3a greater than 2a^2+4a ? (A) a^2-7a (B) a^2+7a (C) -a^2-7a (D) a^2+7a