[" Consider the equation "],[k sin x+cos2x=2k-7]

Consider the equaiton k sinx + cos 2x=2k-7 If the equaiton possesses solution then that what is the minimum value of k ?

The equation k sin x + cos 2 x = 2k - 7 has a solution, if a) k gt 6 b) 2 le k le 6 c) k lt 2 d) -6 le k le -2

Consider the equation sin^(-1)(x^(2)-6x+(17)/(2))+cos^(-1)k=(pi)/(2) , then :

Consider the equation sin^(-1)(x^(2)-6x+(17)/(2))+cos^(-1)k=(pi)/(2) , then :

The solution(s) of the equation sin7x+cos2x=-2 is/are (a) x=(2kpi)/7+(3pi)/(14),\ k in I (b) x=npi+pi/4\ k in I x=2npi+pi/2,\ k in I (d) none of these

The solution(s) of the equation sin7x+cos2x=-2 is/are x=(2kpi)/7+(3pi)/(14),\ k in I (b) x=npi+pi/4\ k in I x=2npi+pi/2,\ k in I (d) none of these

The equation k sinx + cos2x = 2k -7 possesses a solution if :

The equation k sinx + cos2x= 2k-7 has a solution if

The value of K so that the equation (K+1)sin x+2cos x=2+K has at least one solution.

The value of K so that the equation (K+1)sin x+2cos x=2+K has at least one solution is