66x+6y=7x+3y+1=2(x+6y-1)

6x + 5y = 7x + 3y + 1 = 2 ( x + 6y - 1 )

y-1=m_1(x-3) and y - 3 = m_2(x - 1) are two family of straight lines, at right angled to each other. The locus of their point of intersection is: (A) x^2 + y^2 - 2x - 6y + 10 = 0 (B) x^2 + y^2 - 4x - 4y +6 = 0 (C) x^2 + y^2 - 2x - 6y + 6 = 0 (D) x^2 + y^2 - 4x - by - 6 = 0

Solve for x and y : (1)/( 7x ) + ( 1) /( 6y) = 3, (1)/( 2x) - (1)/( 3y ) = 5 (x ne 0, y ne 0)

If 10y=7x-4 and 12x+18y=1 . Find the value of 4x+6y and 8y-x .

The angle of intersection of the curves y=x^(2), 6y=7-x^(3) at (1, 1), is

The angle of intersection of the cuves y=x^(2) and 6y=7-x^(3) at (1, 1) is-

The angle of intersection of the curves y=x^(2), 6y=7-x^(3) at (1, 1), is

Find the value fo x:y, if (7x - 15y)/(4x + 6y) = (5)/(6).

Solve the following system of equations: (1)/(7x)+(1)/(6y)=3,quad (1)/(2x)-(1)/(3y)=5