[" 4.The function "f:(0,oo)-R" given by "f(x)=],[[x/(x+1)" is "square F],[(2" Points) "]]

The function f:[0,oo] to R given by f(x)=(x)/(x+1) is

The function f:R to R given by f(x)=x^(2)+x is

The function f:R to R given by f(x)=x^(2)+x is

The function f : [0,oo)to[0,oo) defined by f(x)=(2x)/(1+2x) is

The function f : (0, oo) rarr [0, oo), f(x) = (x)/(1+x) is

The function f : (0, oo) rarr [0, oo), f(x) = (x)/(1+x) is

The function f:[0,\ oo)->R given by f(x)=x/(x+1) is (a) one-one and onto (b) one-one but not onto (c) onto but not one-one (d) neither one-one nor onto

The function f:[0,\ oo)->R given by f(x)=x/(x+1) is (a) one-one and onto (b) one-one but not onto (c) onto but not one-one (d) neither one-one nor onto

A function f:[0,oo)to[0,oo) defined as f(x)=(x)/(1+x) is :

Prove that the function f: [0,oo)rarr R , given by f(x) =9x^(2) +6x -5 is not invertible. Modify the codomain of the functions to make it invertible, and hence find f^(-1)