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4G 33%, D OK/s tsl 8:49 PM 4G LTE The An...

4G 33%, D OK/s tsl 8:49 PM 4G LTE The Answer is- Optio 81 y 18y 81 0 The Answer is- Optio

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Tick the correct answer and justify: Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio (A) 2:3 (B) 4:9 (C) 81:16 (D) 16:81

A circle S passes through the point (0, 1) and is orthogonal to the circles (x -1)^2 + y^2 = 16 and x^2 + y^2 = 1 . Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

A circle S passes through the point (0, 1) and is orthogonal to the circles (x -1)^2 + y^2 = 16 and x^2 + y^2 = 1 . Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

Tick the correct answer and justify:ABC and BDE are two equilateral triangles such that D is the mid point of BC Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio (A) 2:3 (B) 4:9 (C) 81:16 (D) 16:81

A circle S passes through the point (0, 1) and is orthogonal to the circles (x -1)^2 + y^2 = 16 and x^2 + y^2 = 1. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

The circles x^2 + y^2 - 4x - 81 =0 and x^2 + y^2 + 24x - 81=0 intersect each other at A and B . The equation of the circle with AB as the diameter is : (A) x^2 + y^2 = 81 (B) x^2 + y^2 = 9 (C) x^2 + y^2 = 16 (D) x^2 + y^2 = 1

The circles x^2 + y^2 - 4x - 81 =0 and x^2 + y^2 + 24x - 81=0 intersect each other at A and B . The equation of the circle with AB as the diameter is : (A) x^2 + y^2 = 81 (B) x^2 + y^2 = 9 (C) x^2 + y^2 = 16 (D) x^2 + y^2 = 1

If y = (1 + tan A) (1 - tan B), where A -B=pi/4 then (y+ 1)^(y + 1) is equal to ............ A) 9 B) 4 C) 27 D) 81