A polynomial `p(x)=ax^2+bx+c` where `a,b,c` are some rational has `1+sqrt(3)` as one of the zeroes and also `p(2)=-2` Find the values of `a,b and c`.

The polynomial p(x)=ax^(2)+bx+c can have at most zeros, where ane0 :

If x=0 and x=-1 are the zeroes of the polynomial p(x)=2x^3-3x^2+ax+b , find the value of a and b.

lf p(x) = ax^2 + bx+c , then -b/a is equal to   :

If p(x) = ax^(2) + bx + c , then -b/a is equal to

What will be one of the zeroes of p(x) = ax^2 +bx+c " if " a+c=b ?

Consider a cubic polynomial p(x)=ax^(3)+bx^(2)+cx+d where a,b,c,d are integers such that ad is odd and bc is even. Prove that not all roots of p(x) can be rational

If -2 is a zero of the polynomial ax^(3)+bx^(2)+x-b and the value of the polynomial is 4 at x=2 then find the values of a and b.

If (x-1)^(2) is a factor of ax3+bx2+c, find the value of a+b+c

Polynomial p(x)=ax^(2) + bx + c has two zeroes -2 and 1/2 .It leaves a remainder 12 when divided by x-2 .The values of a b and c are

If p(x)=ax^2+bx+c has no real zeroes and a+b+c<0,then