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A simple pendulum is released from rest ...

A simple pendulum is released from rest at the horizontally stretched position. When the string makes an angle `theta` with the vertical, the angle `theta` which the acceleration vector of the bob makes with the string is given by–

A

`phi = 0`

B

`varphi = tan^(-1)((tan theta)/(2))`

C

`varphi = tan^(-1)(2tantheta)`

D

`varphi = pi//2`

Text Solution

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The correct Answer is:
B
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