" (b) "x^(6)y^(9)-1

The equation of the circle touching Y-axis at (0,3) and making intercept of 8 units on the axis (a) x^(2)+y^(2)-10x-6y-9=0 (b) x^(2)+y^(2)-10x-6y+9=0 (c) x^(2)+y^(2)+10x-6y-9=0 (d) x^(2)+y^(2)+10x+6y+9=0

[" The solution of equation "],[log((dy)/(dx))=9x-6y+6;" given that "],[y(0)=1" is "],[[" (1) "4e^(6y)=3e^(9x+6)+e^(6)," ( ) "],[" (2) "3e^(6y)=4e^(9x+6)-e^(6)," 3e "6y=2e^(9x+6)+e^(6)],[" (4) "2e^(6y)=3e^(9x+6)-e^(6)]]

Factorize: (i)9-a^6+2a^3b^3-b^6 (ii)x^(16)-y^(16)+x^8+y^8

The area of the region given by x^(2)+y^(2)-6y<=0&y<=x is (9 pi-9)/(4)b(9 pi-18)/(4)c.(3 pi+9)/(4)d .none of these

Which expression is equivalent to (9x^(2)y^(6))^(-(1)/(2)) ?

Find the square root of (a) -8-6i (b) (x^2)/(y^2)+ (y^2)/(x^2)-(1)/(i) ((x)/(y)-(y)/(x))-(9)/(4) .

If the circles x^(2)+y^(2)=a and x^(2)+y^(2)-6x-8y+9=0 touch externally then a= a.1 b.-1 c.21 d.16

Q. If 2[[x,9],[y,6]]+3[[1,-1],[0,2]]=[[9,15],[12,18]], then the values of (x+y) is (A) 3 (B) 9 (C) -1 (D) -2

Q. If 2[[x,9],[y,6]]+3[[1,-1],[0,2]]=[[9,15],[12,18]], then the values of (x+y) is (A) 3 (B) 9 (C) -1 (D) -2

(6,0),(0,6),a n d(7,7) are the vertices of a A B C . The incircle of the triangle has equation. (a) x^2+y^2-9x-9y+36=0 (b) x^2+y^2+9x-9y+36=0 (c) x^2+y^2+9x+9y-36=0 (d) x^2+y^2+18 x-18 y+36=0