(0.1)3x+4y=10,2x-2y=2

Solve 3x+4y=10; 2x-2y=2

3x+2y=1, 6x+4y=

The equation of the circle whose diameter is the common chord of the circles; x^2+y^2+3x+2y+1=0 and x^2+y^2+3x+4y+2=0 is: x^2+y^2+8x+10 y+2=0 x^2+y^2-5x+4y+7=0 2x^2+2y^2+6x+2y+1=0 None of these

Solve the following pair of the equations: 10/(3x+2y)-4/(2x+y)=1, 2/(3x+2y)+3/(2x+y)=23/20

Find the values of (x-y) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 3x + 2y = 8 , 2x + 3y = 7

3x + 4y - 10 = 0 2x - 2y-2=0

The centres of 3 circles x^2+y^2 =1, x^2+y^2 +6x-2y=1, x^2+y^2-12x+4y=1 are :

From the sum of x^2+3y^2-6x y ,2x^2-y^2+8x y , y^2+8 and x^2-3x y\ subtract -3x^2+4y^2-x y+x-y+3.

From the sum of x^2+3y^2-6x y ,2x^2-y^2+8x y , y^2+8 and x^2-3x y\ subtract -3x^2+4y^2-x y+x-y+3.