[" 03."2(ax-by)+a+4b=0],[qquad 2(bx+ay)+b-4a=0quad [" CBSE "2]

2(ax-by)+(a+4b)=0,2(bx+ay)+(b-4a)=0

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

Solve the following pair of linear equations 2(ax-by)+(a+4b)=02(bx+ay)+(b-40=0

ax+by=a+b bx+ay=b^2

The straight line x-y-2=0 cuts the axis of x at A. It is rotated about A in such a manner that it is perpendicular to ax+by+c=0. Its equation is: (a) bx-ay-2b=0 (b) ax-by-2a=0 (c) bx+ay-2b=0 (d) ax+by+2a=0

If ax^(2)-bx=ay^(2)+by , then (a)/(b)=

If the equation ax^2 +2hxy + by^2 = 0 and bx^2 - 2hxy + ay^2 =0 represent the same curve, then show that a+b=0 .

If the equation ax^2 +2hxy + by^2 = 0 and bx^2 - 2hxy + ay^2 =0 represent the same curve, then show that a+b=0 .

If ax + by = a^(2)-b^(2) and bx + ay = 0, find the value of x + y .

ax+by=a-b;bx-ay=a+b