" If "/_C=90^(@)" in "/_ABC" ,then find "tan^(-1)(a)/(b+c)+tan^(-1)(b)/(c+a)

If angleA=90^(@) in the DeltaABC , then tan^(-1)((c)/(a+b))+tan^(-1)((b)/(a+c)) is equal to

If angle A = 90 ^(@) in the triangle ABC, then tan ^(-1) (( c )/(a+b)) + tan ^(-1) ((b)/(a+c)) is equal to : a)0 b)1 c) (pi)/(4) d) (pi )/(6)

In triangleABC , if angleA=90^(@)", then "tan^(-1)((c)/(a+b))+tan^(-1)((b)/(a+c))=

In triangleABC , if angleA=90^(@)", then "tan^(-1)((c)/(a+b))+tan^(-1)((b)/(a+c))=

If in triangle ABC, C = 90^circ then prove that tan^(-1) (a/(c+b)) + tan^(-1) (b/(a+c)) = pi/4 .

In a A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))=

In a DeltaABC , if mangleA=90^(@) , prove that "tan"^(-1)b/(a+c)+"tan"^(-1)c/(a+b)=pi/(4) , where a,b, c are sides of the triangle.

If C is a right angle in the triangle ABC, show that, tan^(-1) 'a/(b+c)' + tan^(-1) 'b/(c+a)' = pi/4 .

In a triangle ABC "if" m/_A =90^@, "prove that "tan"^(-1) b/(a+b) +"tan"^(-1) c/(a+b) =pi/4 . where a,b,c, are sides of the triangle.