[" 2."2x-y=6],[x-y=2]

Solve the following system of linear equations by matrix method: x + 2y + z = 6, 2x + y + 2z=6, x - y - z = 2

If 2x-y = 7 and x-y = 6, then value of x and y will be

The centre of similutude of the circles x^(2)+y^(2)-2x-6y+6=0, x^(2)+y^(2)=1 is

The centres of similutude of the circles x^(2)+y^(2)-2x-6y+6=0, x^(2)+y^(2)=1 is

Solve x+y+z=2 2x+y-z=6 3x+2y+2z=6

Prove that the radii of circles x^2 + y^2 = 1, x^2 + y^2 - 2x -6y = 6 and x^2 + y^2 - 4x - 12y = 9 are in A.p.

Radii of circles x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 6y= 6 and x^(2) + y^(2) - 4x - 12y = 9 are in

Prove that the radi of the circles x^(2)+y^(2)=1x^(2)+y^(2)-2x-6y=6 and x^(2)+y^(2)-4x-12y=9 are in arithmetic progression.

The centres of 3 circles x^2+y^2 =1, x^2+y^2 +6x-2y=1, x^2+y^2-12x+4y=1 are :