`3+5x+9x^2+15 x^3+23 x^4+33 x^5+...........oo(|x| < 1)`

Find the sum of series 4 - 9x + 16 x^(2) - 25 x^(3) + 36 x^(4) - 49 x^(5) + ...oo

Find the sum of series 4 - 9x + 16 x^(2) - 25 x^(3) + 36 x^(4) - 49 x^(5) + ...oo

Find the sum of series 4 - 9x + 16 x^(2) - 25 x^(3) + 36 x^(4) - 49 x^(5) + ...oo

lim_(x to 3) (x^(3) - x^(2) + 15 x - 9)/(x^(4) - 5x^(3) + 27x - 27) is equal to

Find the sume of the series 4-9x+16x^(2)-25x^(3)+36x^(4)-49x^(5)+...oo

(1+x^2/(2!) +x^4 /(4!) + .....oo)^(2) - (x+x^3/(3!) +x^(5)/(5!) + ....oo)^(2) =

Evaluate lim_(x to 3) (x^(3) - 7x^(2) + 15x - 9)/(x^(4) - 5x^(3) + 27 x - 27)

Sum 1+3x+5x^(2)+7x^(3)+9x^(4)+...... to oo is (x<1)

Find the intervals in which the following function are increasing or decreasing. f(x)=10-6x-2x^2 f(x)=x^2+2x-5 f(x)=6-9x-x^2 f(x)=2x^3-12 x^2+18 x+15 f(x)=5+36 x+3x^2-2x^3 f(x)=8+36 x+3x^2-2x^3 f(x)=5x^3-15 x^2-120 x+3 f(x)=x^3-6x^2-36 x+2 f(x)=2x^3-15 x^2+36 x+1 f(x)=2x^3+9x^2+20 f(x)=2x^3-9x^2+12 x-5 f(x)=6+12 x+3x^2-2x^3 f(x)=2x^3-24 x+107 f(x)=-2x^3-9x^2-12 x+1 f(x)=(x-1)(x-2)^2 f(x)=x^3-12 x^2+36 x+17 f(x)=2x^3-24+7 f(x)=3/(10)x^4-4/5x^3-3x^2+(36)/5x+11 f(x)=x^4-4x f(x)=(x^4)/4+2/3x^3-5/2x^2-6x+7 f(x)=x^4-4x^3+4x^2+15 f(x)=5x^(3/2)-3x^(5/2),x >0 f(x)==x^8+6x^2 f(x)==x^3-6x^2+9x+15 f(x)={x(x-2)}^2 f(x)=3x^4-4x^3-12 x^2+5 f(x)=3/2x^4-4x^3-45 x^2+51 f(x)=log(2+x)-(2x)/(2+x),xR