Find the area of the triangle whose two sides are 11 and 5 cm and perimeter is 30 cm

Explanation

a+b+c=32

8+11+c=32

c=13

`S=(a+b+c)/2=32/2=16`

Area of triangle`=sqrt(s(s-a)(s-b)(s-c)`

`=sqrt(16*8*5*3)`

`=8sqrt30cm^2`.