[" QUESTION 6: "],[cos(tan^(-1)sin(cot^(-1)x))=]

cos[tan^(-1){sin(cot^(-1)x)}] is equal to

Solve : cos(tan^(-1)x)=sin(cot^(-1)""(3)/(4))

sin(Cot^(-1)(cos(Tan^(-1)x)))=

sin[cot^(-1){cos(tan^(-1)x)}]=

Solve cos(tan^-1x) = sin(cot^-1 (3/4))

sin {cot^(-1)[tan (cos^(-1)x)]=

Find the value of, cos [tan^(-1) {sin (cot^(-1)x)}]

Solve the following equation for x : "cos"(tan^(-1)x)=sin(cot^(-1)(3/4)) , tan(cos^(-1)x)=sin(cot^(-1)(1/2))