20x^(2)-45

What is the remainder when 3x^(4)-2x^(3)-20x^(2)-12 is divided by x+2?

Solve for x:x^(4)-20x^(2)+64=0 .

When the origin is shifted to (-2,-3) and the axes are rotated through an angle 45^(0) , find the transformed equation of 2x^(2)+4xy-5y^(2)+20x-22y-14 = 0 .

Fractorise: 20a ^(2) - 45 b ^(2)

Divide : ( 20a^(2) - 15 ab + 45a ) by (5a)

What does the equation 2x^(2)+4xy-5y^(2)+20x-22y-14=0 become when referred to the rectangular axes through the point (-2,-3), the new axes being inclined at an angle at 45^(@) with the old axes?

10x^(2)-20x+1=0