A parallel plate capacitor of capacitance `C_(0)` is charged with a charge `Q_(0)` to a potential difference `V_(0)` and the battery is then disconnected Now a dielectric slab of dielectric constant `k` is inserted between the plates ofcapacitor. The dimensions of the slab are such that it completely fills the space between the plates, then :

Options

A. Charge on the' plates remains the same
B. Charge on the plates decreases to `Q_(0)//K`
C. Charge on _the plates increases to `KQ_(0)`
D. Potential difference between plates remains the same

Answer

A