Home
Class 12
PHYSICS
Two square metal plates of side 1 m are ...

Two square metal plates of side `1 m` are kept `0.01 m` apart like a parallel plate capacitor in air in such a way that one of their edges is perpendicualr to an oil surface in the a tank filled with an insulating oil. The plates are connected to a battery of emf `55 V`. The plates are then lowered vertically into the oil at a speed of `0.001 ms^(-1)`. Calculate the current drawn from the battery during the process.
(Dielectric constant of oil `=11, epsilon_(0) = 8.85 xx 10^(-12) N^(-1) m^(-2))`.

Text Solution

Verified by Experts

The correct Answer is:
`4.425xx10^(-9)A`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CAPACITANCE

    PHYSICS GALAXY - ASHISH ARORA|Exercise ADVANCE MCQS|26 Videos
  • ATOMIC PHYSICS

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problems|39 Videos
  • CURRENT ELECTRICITY

    PHYSICS GALAXY - ASHISH ARORA|Exercise All Questions|389 Videos

Similar Questions

Explore conceptually related problems

Two square metallic plates of 1m side are kept 0.01m apart, like a parallel plate capacitor, in air in such a way that one of their edges is perendicular, to an oil surface in a tank filled with an isulating oil. The plates are connected to a battery of e.m.f. 500 volt. The plates are then lowered vertically into the oil at a speed of 0.001 m//s . Calculate the current drawn from the battery during the process. [di-electirc constant of oil = 11, in_(0) = 8.85 xx 10^(-12) C^(2)//N^(2)m^(2)]

A thin metal plate P is inserted between the plates of a parallel-plate capacitor of capacitance C in such a way that its edges touch the two plates (figure 31-Q2).The capacitance now becomes.

Knowledge Check

  • Two square metallic plates of side a =1 m are kept at d = 8.85 mm apart, like a parallel plate capacitor, in such a way that their surfaces are normal to the oil surface are normal to the oil surface in a tank filled with insulating oil (K = 11). The plates are connected to a battery of emf V = 500 volt as shown in figure. The plates are then lowered vertically into the oil at a speed of v = 10^(-3)ms^(-1) . Negalecting resistance of connecting wires, calculate the current drawn from battery during the process ( epsi_(0)=8.85xx10^(-12)C^(2)N^(-1)m^(-2) )

    A
    `5xx10^(-19)`A
    B
    `0.5xx10^(-19)`A
    C
    `5xx10^(-9)`A
    D
    None of these
  • If we pull apart the plates of parallel plate capacitor then,

    A
    The capacitance increases
    B
    Total charge increases
    C
    The potential difference increases
    D
    Capacitance increases
  • A parallel plate capacitor is charged. If the plates are pulled apart

    A
    the potential difference increases
    B
    the capacitance increases
    C
    the total charge increases
    D
    the charge and the potential difference remain the same
  • Similar Questions

    Explore conceptually related problems

    A parallel plate capacitor has capacitance of 1.0 F . If the plates are 1.0 mm apart, what is the area of the plates?

    The plates of a parallel plate capacitor have surface area A and are initially separated by a distance d .They are connected to a battery of voltage v_(0) . Now,the plates of the capacitor are pulled apart to a separation 2d.Then increase in the energy of the battery is ..

    A parallel plate capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved farther apart by means of insulating handles:

    A parallel plate capacitor has capacitance of 1.0 F .If the plates are 1mm apart, area of the plates is

    A parallel plate capacitor is connected to a battery and inserted a dielectric plate between the place of plates then which quantity increase