The plates of a parallel plate capacitor are separated by a distance `d = 1 cm`. Two parallel sided dielectric slabs of thickness `0. 7cm` and `0.3cm` fill the space between the plates. If the dielectric constants of the two slabs are 3 and 5 respectively and a potential difference of `440V` is applied across the plates. Find (a) The electric field intensities in each of the slabs. (b) The ratio of electric energies stored in the first to that in the second dielectric slab.

Answer

(a) `5xx10^(4)V//m`, `3xx10^(4)V//m`; (b) `35//9`