If a composite physical quantity in terms of moment of inertia I, force F, velocity v, work W and length L is defined as,
`Q = (IFv^(2)//WL^(3))`,
find the dimensions of Q and identify it.

If I is moment of inertia, F is force, v is velocity, E is energy and L is length then, dimension of (IFv^2/(EL^4)) will be:

A physical quantity X is defined by the formula X=(IFv^(2))/(WL^(3)) where I is moment of inertia, F is force, v is velocity, W is work and L is length, the dimensions of X are

Identify the physical quantity x defined as x = (I F upsilon^2)/(W I^3), where I is moment of inertia, F is force, upsilon is veloicty, W is work and I is length.

Identify the physical quantity x defined as x = (I F upsilon^2)/(W I^3), where I is moment of inertia, F is force, upsilon is veloicty, W is work and I is length.

If F is the force, v is the velocity and A is the area, considered as fundamental quantity . Find the dimension of youngs modulus.

The time period (T) of a physical pendulum depends on the physical quantities 'I' moment of inertia (kgm^(2)) , 'm' mass (kg), 'g' acceleration due to gravity (m//s^(2)) . 'l' length (m). Then which of following may be correct

If alpha=F/v^(2) sin beta t , find dimensions of alpha and beta . Here v=velocity, F= force and t= time.

We know that every derived quantity can be written in terms of some of the fundamental quantities. For example, volume = ("length")^(3), "speed" = ("lenght")/("time") . Using the definitions of the following quanitities, express force in terms of fundamental quantities. Represent mass as [M], length as [L] and time as[T]. (i) Displacement = shortest distance betweenj the inital and final positions. (ii) Velocity = ("displacement")/("time") (iii) Momentum = "mass" xx "velocity" brgt (iv) Force = ("momentum")/("time")

Using force (F), length (L) and time (T) as base quantities , find the dimensions of (i)mass, (ii)surface tension and (iii)Young's modulus.