Home
Class 11
PHYSICS
P = (nx^(y)T)/(V(0))e^(-(Mgh)/(nxT)), wh...

`P = (nx^(y)T)/(V_(0))e^(-(Mgh)/(nxT))`, where n is number of moles, P is represents acceleration due to gravity and h is height. Find dimension of x and value of y.

Text Solution

Verified by Experts

The correct Answer is:
`[ML^(2)T^(-2)K^(-1) mol^(-1)J, y = 1]`,
Promotional Banner

Topper's Solved these Questions

  • UNIT AND DIMENSIONS

    ANURAG MISHRA|Exercise Only one Alternative is Correct|25 Videos

  • UNIT AND DIMENSIONS

    ANURAG MISHRA|Exercise More than One Alternatives are Correct|5 Videos

  • UNIT AND DIMENSIONS

    ANURAG MISHRA|Exercise Matching Type Problem|4 Videos

  • RIGID BODY MOTION

    ANURAG MISHRA|Exercise MATCH THE COLUMN|12 Videos

  • WORK AND ENERGY

    ANURAG MISHRA|Exercise Matching types problems|14 Videos

Similar Questions

Explore conceptually related problems

Find ratio of acceleration due to gravity g at depth d and at height h where d=2h

The velocity of a freely falling body changes as g^ph^q where g is acceleration due to gravity and h is the height. The values of p and q are

Let us consider an equation (1)/(2)muepsilon^2 = mgh, Where m is the mass of the body, upsilon its velocity, g is acceleration due to gravity and h is the height. Check whether this equation is dimensionally correct.

Acceleration due to gravity as same at height h from surface and at depth h from surface, then find value of h

The acceleration due to gravity becomes (g)/(16) at a height of nR from the surface of earth. Find the value of n.

Find the dimensions of K in the relation T = 2pi sqrt((KI^2g)/(mG)) where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

The value fo x in the formula Y = (2mg l^(x))/(5bt^(3)e) where m is the mass, 'g' is acceleration due to gravity, l is length , 'b' is the breath, 't' is the thickness and e is the extension and Y is Young's Modulus is

A particle of mass m is fired vertically upward with speed v_(0) (v_(0) lt " escape speed ") . Prove that (i) Maximum height attained by the particle is H = (v_(0)^(2)R)/(2gR - v_(0)^(2)) , where g is the acceleration due to gravity at the Earth's surface and R is the Earth's radius . (ii) When the particel is at height h , the increase in gravitational potential energy is (mgh)/(1+h/R)

The Bernoulli's equation is given by P+1/2 rho v^(2)+h rho g=k . Where P= pressure, rho = density, v= speed, h=height of the liquid column, g= acceleration due to gravity and k is constant. The dimensional formula for k is same as that for:

The acceleration due to gravity at a height h is given by g_(h)=g((R )/(R+h))^(2) , where g is the accleeration due to gravity on the surface of earth. For h lt lt R , find the value of g using the Binomial theorem.