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(9pi)/8-9/4"sin"^(-1)1/3=9/4sin^(-1)((2s...

`(9pi)/8-9/4"sin"^(-1)1/3=9/4sin^(-1)((2sqrt(2))/3)`

Text Solution

Verified by Experts

The correct Answer is:
`=9/4sin^(-1)[sqrt(8/9)]`
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